X-Chain
Loading demo...
An X-Chain is an AIC (alternating inference chain) involving a single candidate digit. Every node in the chain refers to the same candidate digit, and its strong links come from conjugate pairs for that digit.
How to spot it
- For each candidate
xfrom1to9, find its conjugate-pair strong links: houses in which only two cells can containx. - Connect several strong links using weak links between nodes that see each other. The resulting chain must alternate between strong and weak links, and start and end with strong links, for example
[Ca:x]━[Cb:x]┉[Cc:x]━[Cd:x]┉…┉[Cy:x]━[Cz:x]. - Check the other cells that see both end nodes,
[Ca:x]and[Cz:x], and eliminate candidatexfrom them. There may be more than one elimination.
How it works
- An X-Chain is an AIC for a single candidate
x, with strong links supplied only by conjugate pairs. - In an X-Chain of the form
[Ca:x]━[Cb:x]┉[Cc:x]━[Cd:x]┉…┉[Cy:x]━[Cz:x], ifCadoes not containx, thenCbmust containx(strong link). This preventsCcfrom containingx(weak link), which forcesCdto containx(strong link). Continuing along the chain eventually forcesCzto containx. The same reasoning works in reverse: ifCzdoes not containx, thenCamust containx. - Therefore, the end nodes
[Ca:x]and[Cz:x]form a logical strong link: at least one ofCaandCzmust containx. - Any other cell that sees both cells cannot contain
x, so candidatexcan be eliminated from it.
Examples
On the board above, candidate 3 forms the X-Chain [R6C1:3]━[R1C1:3]┉[R1C9:3]━[R2C9:3]┉[R2C5:3]━[R5C5:3]. By the rules of AICs, at least one of R6C1 and R5C5, the cells containing the end nodes, must contain 3. Candidate 3 can therefore be eliminated from any other cell that sees both end nodes. Note that there may be several such cells.
On the board above, candidate 4 forms the X-Chain [R2C9:4]━[R3C9:4]┉[R3C3:4]━[R6C3:4]┉[R5C2:4]━[R5C5:4]┉[R7C5:4]━[R7C6:4]. At least one of R2C9 and R7C6, the cells containing the end nodes, must contain 4, so candidate 4 can be eliminated from any other cell that sees both end nodes.
The board above contains an X-Chain for candidate 4 whose end nodes happen to lie in the same column.